Question

2. How many grams of aluminum form from 10.5g of aluminum oxide if the yield is 95%?
Al2O3 + 3C --> 2Al + 3CO

Answer 1

You would get 5.28 grams of Al:

It is just long stoichiometry:
(10.5 g Al2O3)(1 mol Al2O3/101.96 g)(2 mol Al formed/1mol Al2O3 used)(26.98 g Al/1 mol Al)(0.95 g formed/1.0 g anticipated) Just multiply it all out.

Answer 2

and how do i multiply it out?

Answer 3

Write them out as fractions. Then multiply all the numerators, and divide by all the denominators.

Answer 4

how am i supposed to write it as a fraction. i dont get chemestry at all

Answer 5

It is not chemistry, it is proportionality.
The fractions mentioned by BTaylor help you understand all this.

Answer 6

I dont get any of this at all

Answer 7

Ok, let's go:
1st step : what is the molar mass of aluminium oxide?

Answer 8

i dont know..

Answer 9

In this case, you have to look up Al and O in the periodic table and find their molar masses.
Al = 27 g/mol
O = 16 g/mol

So Al2O3 = ??

Answer 10

43g/mol

Answer 11

This would be molar mass for AlO.

Here, the compound has 2 aluminium and 3 oxygen.