Question

integral of e^(-4x)dx from 0 to 1

Answer 1

hi jackie....:)

Answer 2

heloo there

Answer 3

so i know to use u sub

Answer 4

yes... u-sub..
what answer did u get, or where did u get stuck?

Answer 5

i got \[-1/4\int\limits_{0}^{-4}e^udu\]

Answer 6

i dont remember where to go next

Answer 7

everythings good, just evaluate interal of e^u from 0 to -4....

Answer 8

but since its from 0 to -4 i thought there was another step

Answer 9

there is nothing wrong with the limits just because the top one is less than the bottom one... you can still evaluate it...

Answer 10

you dont have to negate the whole thing?

Answer 11

but if you want, you can go from -4 to 0 and make that -1/4 outside the integral to 1/4...
no, the integral is correct the way it is.... it is EQUIVALENT to: \[\frac{1}{4} \int_{-4}^0 e^u du \]

Answer 12

would it be \[1/4\int\limits_{-4}^{0}e^udu\]

Answer 13

hahaha weird

Answer 14

it's a property of integrals... switch the limits and you'll get the opposite integral...

Answer 15

ok, so i could do it the way it was

Answer 16

\[\large \int_a^b f(x) dx =-\int_b^a f(x) dx \]

Answer 17

yes....:)

Answer 18

gotchaaa :)

Answer 19

great.... :)