How would you remove the discontinuity of the function f(x) = (x^2-x-2)/(x-2)?

Question

turingtest · Answer

for a removeable discontinuity at a point x=a that means that$$\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)\neq f(a)$$all you have to do to remove the discontinuity is redefine the point at x=a to be$$f(a)=\lim_{x\to a}f(x)$$

turingtest · Answer

so...
where is this function discontinuous?
what is the limit at that point?
now redefine the function value at that point to be the limit by making it a step[ function

shayaan_mustafa · Answer

Hi gregtuck1 :)

Kindly answer to TurningTest's post.

Don't you want to learn anything either you want just anyone solve it for you?

amistre64 · Answer

Lets not badger the asker; there are more than one reason why a person could not respond.

anonymous · Answer

This is my first time using this forum and i'm not sure how it works. As a matter of f act, I just figured out how to respond back after trying to figure it out for 5 minutes.

amistre64 · Answer

its this little box on the bottom right :)

amistre64 · Answer

esentiallyy, factor the top and see what cancels is another route to take

anonymous · Answer

The actual question asks, "how would you define f(2) in order to make f continuous at 2?" Any hints on this? thx

amistre64 · Answer

same hint

anonymous · Answer

ok. thx

turingtest · Answer

amistre's hint is perhaps more generous than mine, but I will repeat it anyway:
for a removeable discontinuity at x=a
redefine$$f(a)=\lim_{x\to a}f(x)$$which it currently is not

anonymous · Answer

Ok. thx. i think i can work with that.