Question

D=ViT+1/2 at2 mean, what does the Two at the end of at mean, is it an expounder? Do I multiply them separately and then multiply? thanks

Answer 1

The formula from kinematics for the distance travelled by an object under constant acceleration \( a \) after starting at an initial velocity \( v_i \) for time \( t \) is
\[ d = v_it + \frac{1}{2}at^2 \]
I hope that clears it up for you.

Answer 2

Notice that if the acceleration \( a = 0 \) then
\[ d = v_it \]
which is exactly what you'd expect: it's just the velocity multiplied by time. This makes sense because if the velocity is constant, then
\[ v_i = \frac{d}{t} \]

Answer 3

Thank you very much