Some steps to construct an angle MNT congruent to angle PQR are listed below. Step 3 is not listed. Step 1 - Use a compass to draw an arc from point Q which intersects the side PQ at point A and the side QR at point B. Step 2 - Draw a segment NT and use the same width of the compass to draw an arc from point N which intersects the segment NT at a point X. Step 3 - Step 4 - Join points N and Y using a straightedge. Which statement describes step 3 correctly?
Use the same width of the compass as AQ and draw an arc from point X which intersects the arc drawn from N in a point Y. Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y. Maintaining the same width of the compass as BQ, draw an arc from point X such that it intersects the arc drawn from N in a point Y. Use the same width of the compass as the width of NX and draw an arc from point X such that it intersects the arc drawn from N in a point Y. @dpaInc
@jim_thompson5910
I can't really draw on here (I tried though), but if you draw it out, you'll see that you'll use the length of AB to reconstruct the angle PQR (but on NT) So the answer is "Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y."
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