Question

Circles
http://screensnapr.com/v/sZabsw.jpg

Answer 1

hey Luke..
Luke, I am your father..

Answer 2

link messed up luke...

Answer 3

weird, hang on lol

Answer 4

Eliminate the parameter and write the following equation in rectangular form:

x= sin(t), y= 3cos(t)

Answer 5

this is not a circle...

Answer 6

:(
i don't like ellipses....

Answer 7

Neither do I..

Answer 8

Oh heck i got it. New one.

Answer 9

wait...
don't you want the equation?

Answer 10

http://screensnapr.com/e/zjaRCh.jpg

Answer 11

I already did it :D

Answer 12

just checking.. what was the equation?

Answer 13

x^2/1 + y^2/9 = 1

Answer 14

for \(\large \frac{x^2}{2^2}+\frac{y^2}{4^2}=1 \)
center (0,0)
a=4
b=2
c^2=a^2-b^2=16-4=12 ---> c=\(\large 2\sqrt{3} \)

Answer 15

vertically elongated ellipse so you'll add/subtract "a" to the y coordinate of the center to get your vertices

do the same for the foci using "c"

Answer 16

break time!!! AFK.....