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differentiation of a quotient with respect to x of y=(ln 2 x)/sqrt x
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Apply the quotient rule.\[\frac {d}{dx} \left[ \frac {u}{v} \right] = \frac {vu' - uv'}{v^2}\]
i think i have done that want to check my answer - i get dy/dx = x^-3/2(1+ln2x/2x) does this seem sensible
It should be x^(-3/2)(1 - ln(2x)/2). You might've made a factoring error.
okay - feel i on the right lines - thank you
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