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Mathematics 7 Online
OpenStudy (anonymous):

Susan drew the diagram shown below and described it as an equilateral triangle with a square inside it. Point D is the midpoint of segment AC. The geometry teacher pointed out that the triangle cannot be equilateral since side AC is not equal to AB. Which statement best explains why the measurements are incorrect?

OpenStudy (anonymous):

@Calcmathlete

OpenStudy (anonymous):

Can you put up the choices?

OpenStudy (anonymous):

of course hold on, sorry I forgot

OpenStudy (anonymous):

Segment AB is 7 + 7 + 7 = 21. Segment AB is 7 + 12 + 7 = 26. Segment AB ≈ 7 + 3.1 + 7 ≈ 17.1. Segment AB ≈ 7 + 9.7 + 7 ≈ 23.7.

OpenStudy (anonymous):

Segment AB ≈ 7 + 9.7 + 7 ≈ 23.7.

OpenStudy (anonymous):

Do you understand why?

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

lol Same time.

OpenStudy (anonymous):

How about I walk you through it?

OpenStudy (anonymous):

sounds great ;)

OpenStudy (anonymous):

Triangle ADE is a right triangle, so use Pythagorean Theorem to get the remaining side to the nearest tenth.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Tell me get.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Tell me what you get

OpenStudy (anonymous):

oh ok, lol had to read you reply two times

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

a2+b2=c2 12+14=c2?

OpenStudy (anonymous):

but theres a missing part in a triangle in side b

OpenStudy (anonymous):

It's a^2 + b^2 = c^2. 7^2 + b^2 = 12^2 49 + b^2 = 144 b^2 = 95 b = √95 b ≈ 9.7

OpenStudy (anonymous):

OoOoHHH

OpenStudy (anonymous):

Then, since b is a side on the square, all of the other sides are equal to 9.7. That means that you can add up 7, 7, and 9.7

OpenStudy (anonymous):

oh ok i see it now!

OpenStudy (anonymous):

Then, double side AD because D is a midpoint, in order to get side AC.

OpenStudy (anonymous):

24 ≠ 23.7

OpenStudy (anonymous):

yea I got it now! THANX SO MUCH!

OpenStudy (anonymous):

You're welcome :)

OpenStudy (anonymous):

i have like 5 more questions..would you help?

OpenStudy (anonymous):

I still havent posted them because im trying to figure it out

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