solve the equation 3 tan x - cot x = 0
Let tan x be equal to u and then solve for u
Remember \[\cot x = 1/tanx\]
3 tan x = cot x 3 tan^2(x) = 1 tan^2(x) = 1/3 \[\tan x = \sqrt{3}/3\] x = 30
so you have \[3u - 1/u = 0\]
what do u mean by u u and x are the same thing
Look at the comment above yours. I wrote it down for you.
ok one
question how did u get tan^2 @jlee7x2
No, your answer would not be one.
3 tan x = 1/tan x 3 tan^2(x) = 1
yes i know that it was a typo
b/c cot x = 1/tan x as @beeqay mentioned
\[3u- 1/u =0\] This is equal to \[3u^2 -1= 0\] Now solve for u
how did u get tan^2 from tan x - 1/tan x
@Nali If you plug in \[tanx \]back into \[u\], then you have \[3\tan^2x -1 = 0\]
But @jlee7x2 just multiplied everything by\[ tanx\] to get rid of \[1/tanx\] You see \[tanx- 1/tanx=0\] is the same as \[\tan^2x -1 = 0\]
yes i got it thanks to all
No problem.
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