A lab technician needs to make 60 mL of 32% nitric acid solution. The acid solutions available are 20% nitric acid solution and 40% nitric acid solution. How many millilitres of each solution should be mixed to make the 32% solution?
if you have 20% of nitric acid...how many % of non-nitric do you add?
i think there is mistake in the question @genius12 since here you have writen 20 nitric acid soln and 40% nitric acid soln , they are both same , can we write it as 60% nitric acid soln ? may be i am wrong
No the question is exactly what I typed
But you might be right, I at first thought that there is something wrong with the question. But maybe there isn't?
what doyou mean @mathslover ?
@lgbasallote i meant that in the 2nd line it is written 20% nitric acid soln and 40% nitric acid soln why is there nitrc acid written two times ? i mean that can it be written as 60% ntric acid soln as a whole
@genius12 like i was saying...if you have 20% nitric acid...how much percent of non-nitric acid do you have?
good going @lgbasallote carry on
12%?
what's 100% - 20%?
are you there @genius12 ?
yes i am
oh 80%
are you there @Igbasallote
are you there @lgbasallote
80% is right...what about for 40%?
60%
and 32%?
68%
good...so you have x mL of 20% nitric acid added to y mL of 40% nitric acid and this results to 60 mL of 32% nitric acid...agree?
yes
good...so can you set up the equation for the non-nitric acid?
no
why not?
I don't feel confident
lol that's fine
just try
plz no
I tried, I know it's easy, and that's what is hard for me -.-
fine..i'll guide you..what is the measurement of the 20% nitric acid? i mean how many mL is it?
I do not know, I haven't found that out
what did i write?
measurement of the 20% nitric acid, in mL
i meant how many mL of 20% did i write?
you didn't
i wrote something...check it again
you did write, but not the mL
look at what i wrote again "good...so you have x mL of 20% nitric acid added to y mL of 40% nitric acid and this results to 60 mL of 32% nitric acid...agree?"
so x + y = 60 and 0.2x + 0.4y = 0.32 Is that correct, and is that what you mean?
no...im just asking how many mL did i say 20% of nitric acid have
80%? You didn't say anything for mL
80% is not mL don't think about numbers...just look at what i said
i didnt say a value yet but i did assign a letter
you said 'x' mL of 20% and 'y' mL of 40%
x mL of 20% <--that's what i was asking...you have x mL...and what did you say the percent of non-nitric is when there is 20% nitric acid?
80%
therefore you have x mL of 80% NON nitric acid..got it?
ya, and y mL of 60% non-nitric acid for other solution
you got it
what abt the result?
ummm
0.8x + 0.6y = 0.32(60) ???
no no...
1. dont set up the equation yet 2. remember what you were doing a while ago...you copied the mL then changed the percentage
I don't understand, what do u want me to do from here
look at what we did a while ago x mL of 20 % nitric acid -> x mL of 80% non-nitric y mL of 40% nitric acid -> y mL of 60% non-nitric 60 mL of 32% nitric acid -> ?
60 ml of 68% non-nitric acid?
yup
now we set up an equation .20 x + .40y = 0.32(60) <---nitric equation .80x + .60y = 0.68(60) <---non-nitric
do you understand that?
yes
now I can solve the linear system for x and y?
good..now simplify it
now I can solve the linear system for x and y?
yup
k ty, my brain is merely working. I am screwing up easy questions and its 1:40 am -.-
it's not simple actually...it needs outside the box thinking lol
well I thought it was simple. But ty for help. =)
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