What are the slopes of the asymptotes for the hyperbola with the equation (x - 2)2 /16 - (y + 3)2 / 25 = 1?

A. +or- 16/25
B. +or- 25/16
C. +or- 5/4
D. +or- 4/5

Question

What are the slopes of the asymptotes for the hyperbola with the equation                        (x - 2)2 /16 - (y + 3)2  / 25  = 1?

	A. +or- 16/25
	B. +or- 25/16
	C. +or- 5/4
	D. +or-  4/5

anonymous · Answer

$$\left( x-2 \right)^{2}/16 - (y+3)^{2}/25 = 1$$

anonymous · Answer

equation of a hyperbola is x^2/a^2 - y^2/b^2 = 1  and the equation of the asymptotes will be y = -(b/a)x and y = (b/a)x

anonymous · Answer

That makes your two equations y = -(5/4)x and y = (5/4)x  and as you know from y = mx + b the m = slope which is + or - (5/4)   Make sense?

anonymous · Answer

Yep Thanks =)

anonymous · Answer

No prob