Diff Eq help anyone?
or this http://openstudy.com/updates/4fd16ab5e4b057e7d220ae39 but ill be glad to help if i can
I've been given an equation, \[(t^2+5t+6)y'+(t-1)y=sint \] And am asked to determine (without solving the equation) an interval in which the solution with given initial conditions is certain to exist. y(-4)=99
I guess I'm confused because p(x) and g(x) are not discontinuous anywhere...so would the interval be -infinity to +infinity?
\[(t^2+5t+6)y'+(t-1)y=\sin t\] \[(t+2)(t+3)y'+(t-1)y=\sin t\] \[y'+\frac{(t-1)}{(t+2)(t+3)}y=\frac{\sin t}{(t+2)(t+3)}\]
can you see some holes if the function now?
Yes! I can. Thank you for pointing that out.
So according to the theorem, t0 needs to lie in the interval, correct?
i dont know the theorem you speak of
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