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\[\ln |3e^{5i+2}\times7e^{{-2i}}|.\]
simplify \(3e^{5i + 2} \times 7e^{-2i}\) first i guess
k! i get \[21e^{3i+2}.\]
then?
hmm ok..this got difficult -_- lol
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try expanding it
\[\ln (21e^{3i + 2} = \ln 21 + \ln e^{3i+2}\]
what are we finding btw @maheshmeghwal9
sorry i didn't get:(
isnt \[ln (bc) = \ln b + \ln c?\]
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it's a logarithmic property \[\large \log_a (bc) = \log_a b + \log_a c\]
so..ln21+3(i)+2=ln21+..? what to write in place of i?
i already know that but how to get answer?
Let me check \[ \large \ln e^{a + ib} = a+ib\]
k! so what is the answer |dw:1339152131514:dw| is it this?
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