Question

Create your own unique quadratic equation in the form y = ax^2 + bx + c. Use complete sentences and show all work to determine the following:

Does the graph open up or down? How do you know? (2 points)
Explain whether the graph has a maximum or minimum point. (2 points)
Find the vertex and x-intercepts of the graph. (3 points)

Answer 1

1.open up

Answer 2

I have to make my own quadratic equation. I don't know how..

Answer 3

well it determines on the quadratic equation if it is negative then down and if positive the up

Answer 4

Simply make one,
x^2-2x+1=0
open up because coefficient of x^2 is postivie

Answer 5

Well, will you help me if I make one real quick? Let's answer this problem with this one. x^2 - 3x + 2 = 0.

Answer 6

well i better start up with the y=x^2

Answer 7

okay, y = x^2 - 3x + 2 = 0.

Answer 8

quadratic equation - \[2x ^{2}+100x-3\]

Answer 9

then to make it more complex add or subtract any number

Answer 10

we'll take x^2 - 3x + 2 = 0
-open up because coefficient of x^2 is positive
-Its minimum because coefficient of x^2 is positive
-complete the square to find the vertex

Answer 11

Okay we will use 2x^2 + 100x - 3.

Answer 12

it has many maximum point but the minimum will about 3 or 4 or 5max

Answer 13

because it is a parabola

Answer 14

I don't know how to complete squares.

Answer 15

Is there a formula?

Answer 16

x^2 - 3x + 2 = 0
(x-3/2)^2-9/4+2=0
(x-3/2)^2-1/4=0
vertex at (3/2,1/4)

Answer 17

vertex at (3/2,-1/4)

Answer 18

What about the x intercept?

Answer 19

factor
x^2 - 3x + 2 = 0
(x-1)(x-2)=0
set each brackets =0 and solve for x

Answer 20

So the x intercepts are (x-1) and (x-2)