how would you simplify this:
(2x+3)^8 1/2(x-2)^-1/2 +(x-2)^1/2 16(2x+3)^7
to this:
1/2(2x+3)^7(x-2)^-1/2 [2x+3 + 32(x-2)]

Question

how would you simplify this:
(2x+3)^8 1/2(x-2)^-1/2 +(x-2)^1/2 16(2x+3)^7
to this:
1/2(2x+3)^7(x-2)^-1/2 [2x+3 + 32(x-2)]

anonymous · Answer

can you please show how you get 32 because i got stuck at that part

anonymous · Answer

you seem to be missing an operation here 2x+3)^8 1/2(x-2  what should be between the 8 and that 1 -- multiplication?

anonymous · Answer

theres nothing between it. its because its a differentiated first using product rule

anonymous · Answer

I haven't a clue what you are asking here. there has to be an operator of some type(+ or *) or else they are two distinct equations.

anonymous · Answer

im lost too, but thank you for trying  =]

apoorvk · Answer

@newkid hey can you use the equation editor to post your equation, or just use the drawing option below? That would make it easier for us :)

anonymous · Answer

okay

anonymous · Answer

is this originally a calc question?  post the initial quesiton and follow apoorvk's advice

anonymous · Answer

differentiate using product rule and simplify:
$$y=(2x+3)^8\sqrt{x-2}$$

anonymous · Answer

@ivan77 yup its a calc question

anonymous · Answer

ah.  remember the product rule is (fg)' = f'g + fg'  ... show what you ahve as the next step.  NOTE: fg means f*g

anonymous · Answer

yup i remeber is this is the answer that i got t $$(2x+3)^8.1/2(x-2)^-1/2 +(x-2)^1/2. 16(2x+3)^7$$

anonymous · Answer

@ivan77 how would you simplify the answer?

anonymous · Answer

@apoorvk heres the question =] differentiate using product rule and simplify:
[y=(2x+3)^8\sqrt{x-2}\]

apoorvk · Answer

|dw:1339161248571:dw|

I guess you'll have to use the quotient rule here. Know it?