ln 8xy=e^(x+y)
I am just having such a hard time figuring it out!
figuring out what?
oh im sorry its find dy/dx
find the derivative
ooh ok it will be easier if you start with \[\ln(8)+\ln(x)+\ln(y)=e^{x+y}\] then take the derivative of both sides wrt \(x\)
you are thinking of \(y\) as a function of \(x\) so when you take the derivative of something involving \(y\) you need the chain rule first step is \[\frac{1}{x}+\frac{y'}{y}=(1+y')e^{x+y}\]
is that step clear? because it is algebra from here on in to solve for \(y'\)
so ln(8) goes away because it is an constant?
yup
how about the rest? because that was the only calc step all other steps are algebra steps
ok so i got [(xye ^{x=y}-y)/(x-xye ^{x+y})\]
oh i didn't do it, but that looks good. let me check
hi @ satelllite how do u write 4/5 in fraction form? please tell:)
|dw:1339162651213:dw| like this in math editor
@MegMegs4 yes i think that is correct @maheshmeghwal9 it is in fraction form
thank you so much
yw
@satellite73 I wanna ask how do write a fraction using Equation editor
like|dw:1339162755176:dw|
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