Question

Solve for t : (1/2)(-32t^2+t+400)

Answer 1

no you cant

Answer 2

How?

Answer 3

you mean simplify?

Answer 4

if its solve then (1/2)(-32t^2+t+400)=0

Answer 5

\[\begin{array}{l} \frac{1}{2} \left(-32 t^2+t+400\right)=0 \\ \text{Divide both sides by }\frac{1}{2} \\ -32 t^2+t+400=0 \\ \text{Use quadratic formula \to solve the equation:} x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\\text{Where a=-32,b=1,c=400}\\\end{array}\]

Answer 6

\[\huge x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
\[\huge x=\frac{-1 \pm \sqrt{1^2-4(-32)(400)}}{2(-32)}\]
\[\huge x=\frac{1 \pm \sqrt{51201}}{64}\]
\[\huge x=\frac{1 + \sqrt{51201}}{64}~~~or~~~\huge x=\frac{1 - \sqrt{51201}}{64}\]

Answer 7

just replace x as t, its the same

Answer 8

Thank you