if the sum of the zeroes of the polynomial px^+5x+8p is equal to the product of the zeroes find the value of p...
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (apoorvk):
@Parvathysubhash - is that a px^2?
OpenStudy (anonymous):
ya
OpenStudy (maheshmeghwal9):
if a & b are roots/zeroes then;\[a+b=ab\] according to ur question:)
then it it;
\[\frac{-b}{a}=\frac{c}{a}.\]
And ur equation is as\[ax^2+bx+c=0.\]
OpenStudy (apoorvk):
Okay, now..
For a quadratic equation of the standard form\[ax^2 + bx + c =0\]the sum of the roots is (-b/a) and the product of the roots is (c/a).
Here your equation is px62 + 5x + 8p = 0, can you compare this with the standard equation and tell me what the 'a' 'b' and 'c' are for this case?
OpenStudy (maheshmeghwal9):
put the values to get ur answer
some common sense would also be used:)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (apoorvk):
** i mean "px^2" over there, not "px62".
OpenStudy (anonymous):
@apoorvk ...a =p, b=5 ,c=8p
OpenStudy (apoorvk):
very well!
now product of roots = c/a
and sum of roots = -b/a.
so what would their value be?
OpenStudy (apoorvk):
*values
OpenStudy (anonymous):
-b/a = -5/p, c/a =8p/p
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
thx i gt it
actually i 4gt to cancel
OpenStudy (anonymous):
p=-5/8??
OpenStudy (apoorvk):
YES!! Right-O!!!!!! :)
OpenStudy (anonymous):
thnq..:D
OpenStudy (apoorvk):
Anytime! :P
Still Need Help?
Join the QuestionCove community and study together with friends!