if the sum of the zeroes of the polynomial px^+5x+8p is equal to the product of the zeroes find the value of p...
@Parvathysubhash - is that a px^2?
ya
if a & b are roots/zeroes then;\[a+b=ab\] according to ur question:) then it it; \[\frac{-b}{a}=\frac{c}{a}.\] And ur equation is as\[ax^2+bx+c=0.\]
Okay, now.. For a quadratic equation of the standard form\[ax^2 + bx + c =0\]the sum of the roots is (-b/a) and the product of the roots is (c/a). Here your equation is px62 + 5x + 8p = 0, can you compare this with the standard equation and tell me what the 'a' 'b' and 'c' are for this case?
put the values to get ur answer some common sense would also be used:)
** i mean "px^2" over there, not "px62".
@apoorvk ...a =p, b=5 ,c=8p
very well! now product of roots = c/a and sum of roots = -b/a. so what would their value be?
*values
-b/a = -5/p, c/a =8p/p
thx i gt it actually i 4gt to cancel
p=-5/8??
YES!! Right-O!!!!!! :)
thnq..:D
Anytime! :P
den nw...hav nthr question
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