Question

(x^5+18x^2-27x)/(x+3)

Answer 1

\[\frac{x^{5}+18x^{2}-27x}{x+3} \]
what do you want to do with it? simplify?

Answer 2

find the quotient

Answer 3

Synthetic division

Answer 4

idk it says find the quotient and enter your answer n the decending order below.

Answer 5

would long division work? i havent done polynomials in a while..

Answer 6

i think so

Answer 7

I think that this is easier; not sure if it would work:
\(P(x)=D(x)*Q(x)\)

Answer 8

You do it like the pic below,
\[x^4-3x^3+9x^2-9x\] is your quotient

Answer 9

num is(x^5+18x^2-27x)
x^5 -3x^4 + 3x^4 + 9x^3 - 9x^3 +27x^2 -9x^2 -27x
=> x^5 - 3x^4 + 9x^3 -9x^2 + 3x^4 -9x^3 + 27x^2-27x
=>x(x^4 -3x^3 + 9x^2-9x) + 3(x^4 -3x^3 + 9x^2-9x)
=>(x^4 -3x^3 + 9x^2-9x)(x+3)

which gives your ans
and by thew way,,long division will also work..

Answer 10

@Mimi_x3 there are other ways, since the remainder is 0, we can say that x=-3 is a factor of (x^5+18x^2-27x)
then f(-3)=x^5+18x^2-27x

Answer 11

but that's finding zero , lol

Answer 12

just use the synthetic division ;)

Answer 13

is it easier

Answer 14

its the same thing i suppose..

Answer 15

okaii