Question

(x-4) - (x + 7) + (x+3)
7y 8y 6y

* problem read like so: x - 4 over 7y minus x + 7 over 8y plus x+ 3 over 6y
this problem has 7 empty places for the numerator and 4 places for the denominator.. . . every answer i get does not fit in the required space. . . please explain.

Answer 1

is it:
\[\large \frac{x-4}{7y} -\frac{x+7}{8y} +\frac{x+3}{6y} \]?

Answer 2

yes

Answer 3

Whatdo you want to do with it?

Answer 4

i have to simplify it but i cant get the right answer

Answer 5

Is\[\frac{31 x-159}{168 y} \]the right answer?

Answer 6

idk if it is bc the automatic checker isnt working can u explain?

Answer 7

Combine the first two fractions. Then combine the result with the third fraction.\[\frac{x-4}{7y }-\frac{x+7}{8y}+\frac{x+3}{6y} \]\[\frac{x-81}{56 y}+\frac{x+3}{6 y} \]\[\frac{31 x-159}{168 y} \]

Answer 8

ok thank you

Answer 9

You are welcome.