Question

Solid A, with a mass mA, is at its melting point TA. It is placed in thermal contact with solid B, with mass mB and specific heat capacity cB and initially at temperature TB (TB > TA). The combination is thermally isolated. A has latent heat of fusion L and when it has melted has specific heat capacity cA. If A completely melts the final temperature of both A and B is:
A. (mAcATA + mBcBTB – mAL)/(mAcA + mBcB)
B. (mAcATA – mBcBTB + mAL)/(mAcA + mBcB)
C. (mAcATA – mBcBTB – mAL)/(mAcA + mBcB)
D. (mAcATA + mBcBTB + mAL)/(mAcA – mBcB)

Answer 1

can somebody explain to me why it is a?

i see that you add the solids together. Then take away the heat of transformation (do you always do this even if it is for evaporation?). Also why do you then divide?

Answer 2

c=specific heat
T=temperature
m=mass
A is block A and B is block B

L= latent heat of fusion

Answer 3

let the final temperature be T....

solve above equation and find your answer....