how do you do integral on x^3-2x-x
When you have a sum or a difference under the sign of an integral, you can split it into many integrals. By doing so, you will have three different integrals, but they will be easy to calculate.
1/4x^4- 2/2x^2-1/2x^2 is that right?
Yes, this is correct, and of course you need to add the arbitrary constant C to your final answer.
+ C o ok and can it be simplyfied in any way?
well, 2/2=1 and you could factor out x^2.
You should simply x^3 - 3x prior to taking integral!
i have 1/4 X^4-3/2 x^2 in my textbook as an answer I don't see how they got there
i have no clue what you did there
no how did you get there
1/4x^4- 2/2x^2-1/2x^2 < how does that get to x³- 3x
1/4 X^4-3/2 x^2 is the answer i have in my book
yesss
ah!
∫ x³ dx = x^4/4 - 3∫ xdx = -3x²/2
-2x-x= -3x
i see it now very simple
thank you very much
Yup, indeed it issss!
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