Question

Figure shows a 'x-t' graph of a particle. Find the time 't' such that the average velocity of the particle during the period 0 to t is zero. & please give reason too that how did u find the answer:)

Answer 1

answer \[\approx12\sec.\]

Answer 2

how?

Answer 3

please don't scale it.
Actually it is a hand made figure in paint:)

Answer 4

figure is not clear

Answer 5

X is distance or displacement..what is it.

Answer 6

Is it HC verma book problem....

Answer 7

ya question 11 at page-52

Answer 8

& it is displacement.

Answer 9

the actual figure @kr7210

Answer 10

the solution which i don't get:/

Answer 11

This is wrong question...because there is no sufficient information to calculate the average velocity from the given graph ...there should be points 2,4,8,10,12,14,etc on the axis ok..

Answer 12

but i have given the solution which i don't get:/

Answer 13

how can it is possible ...

Answer 14

what?

Answer 15

k!k! i have got it thanx:)

Answer 16

now say me what is the displacement at t=0 ..and what is the time at which it will be same to displacement at t=0...find it from the graph..it is impossible to find it from your graph.

Answer 17

think yourself. and who can solve it ,only it can be guess....what have you got?..

Answer 18

i have got that it is only a conceptual question
so we can make the answer \[\approx12.\] & one more thing it is not a particular exam type question, & when it is given in the exam it will have appropriate points & graph.
Am I right? @Taufique

Answer 19

yes you are right now..

Answer 20

k! thanx for helping me upto this^_^

Answer 21

ok..

Answer 22

average value theorem :
F(t1)=f(t2) => exist t f'(t)=0 t1<t<t2 f is continue and derivative.
So f=x is situation and f'=v is velocity

Answer 23

^Rolle's theorem?

Answer 24

but that'd give instantaneous velocity wont it?
i think.. avg velocity = (final displacement vector - initial displacement vector)/ (time interval)
avg v=0 this means, initial displacement = final displacement (in time t)
and graph is of only one direction ie x axis so putting a ruler on graph parallel to x axis.. keeping one end of ruler on initial point find the other point where ruler intersects graph.. ie find next value of t for which displacement is same as starting point
it is somewhat after 10 seconds
of course it cat get any more accurate..

Answer 25

k! thanx for the answer:)