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if x^-1 is a factor of ax^+bx*+cx^+dx+e show that a+c+e=b+d.
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@apoorvk
why are you missing the indices, you need to mention the power. not just "ax^".
ax^ means raised to 2
@apoorvk
lol then write '2' next to '^'. and cx^ means cx^2 as well? as for "dx*"??
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dx*3
I seem to think that it's ax^4 actually - isn't it?
no ax^2
well, the the whole equation is basically: \[bx^3 + (a+c)x^2 + dx + c\] right? that means 1/x completely divides this polynomial.
ya
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brb
hmm
@apoorvk u derrr
yeah, so divide this polynomial by '1/x'! and get the remainder in terms of a,b,c,d,e and equate that to zero. Now rearrange that, and you 'll get the statement to be proved!!
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