x2 + 6x -55 = 0 and root1 = 5, root2 = -11

Question

mathslover · Answer

$$x2 + 6x -55 = 0$$
$$x^2+11x-5x-55=0$$
$$x(x+11)-5(x+11)=0$$
$$(x-5)(x+11)=0$$
$$x=5 , x=-11$$
correct

anonymous · Answer

then what does a=
                       b=
                       c=

mathslover · Answer

where is a , b and c in this equation ?

anonymous · Answer

oh sorry
x2 + 6x -55 = 0 and root1 = 5, root2 = -11
a = ,             b = ,                  c =

mathslover · Answer

sorry i didn;t get u where is a b and c in this eqn ?

anonymous · Answer

thats what they are asking for a,b,c

mathslover · Answer

i think either question is missing or it is wrong

anonymous · Answer

nope I can snip the equation

anonymous · Answer

attachment

anonymous · Answer

thats the full equation

mathslover · Answer

a = 1 , b = 1 , c = -55

mathslover · Answer

is it showing it as right ??

anonymous · Answer

its partial credit

mathslover · Answer

i can not understand by partial credit ?

asnaseer · Answer

the general form of a quadratic equation is:$$ax^2+bx+c=0$$your equation is given as:$$x^2 + 6x -55 = 0$$so compare the coefficients to work out a, b and c.

anonymous · Answer

some of its right, but something is wrong
But I figured it out
the answer is a = 1 , b = 6 , c = -55

asnaseer · Answer

yes - that is the correct answer aussy123.

anonymous · Answer

Thanks

anonymous · Answer

both of you!!

asnaseer · Answer

yw :)

mathslover · Answer

oops big mistake sorry :(

anonymous · Answer

no prob. im just happy you helped

mathslover · Answer

:) thanks this is your gr8ness :)

anonymous · Answer

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