Question

hghghgh

Answer 1

\[1.20 \times 10^{22} atoms \times \frac{1mol}{6.02\times 10^{23}atoms}\times \frac{200g}{1mol}=?\]

Answer 2

4?

Answer 3

yes

Answer 4

.Sam. has used a periodic table to find
\[A_r[\text{Hg]}=200.59\left[\frac{\text{g}}{\text{mol}}\right]\]

Answer 5

''Please explain how you came to your answer''
First find the no. of mole of Hg there.
No. of mole Hg = no. of atoms / Avogadro constant
= 1.20 × 10^22 / 6.02x10^23
= 0.0199 mole
Mass of Hg = no. of mole x atomic mass of Hg
= 0.0199 x 200.59
= 4g