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find dy/dx of y=(sin(x))^x
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ln both sides \[\ln y = x \ln (\sin x)\] do implicit differentiation yada yada...got it?
Yup. Makes sense. thanks.
so can you do it from here?
Yes I can... forgot about implicit. Should be good.
great :D
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Phoenix, do you know why we use log differentiation here?
Phoenix, do you know why we use log differentiation here?
This would be helpful for the future. \[d/dx (a^b) = 0\] because a and b are just constants. \[d/dx (x^n) = nx^{n-1}\] \[d/dx (f(x)^{g(x)}= \log differentiation\] because it's a function raised to a function.
n is a constant in the second case.
Thanks beeqay. Helpful to know that.
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