Question

Help with two algebra equations

Answer 1

^^^^

Answer 2

\[\sqrt{12}/\sqrt{-6}=i \sqrt{2}\]

Answer 3

@ahaines14 its supposed to be a fraction

Answer 4

with complex numbers i^2 = -1

so the problem can be written as

\[\frac {\sqrt{12}}{\sqrt{-6}} = \sqrt{\frac{12}{-6}} = \sqrt{-2}\]

then using i^2

\[\sqrt{-2} = \sqrt{i^2 \times2} = i \sqrt{2}\]

Answer 5

question 2 has the binomials in the numerator will result in the diffference of 2 squares

\[\frac{2+ \sqrt{-3}}{2} \times \frac{2 - \sqrt{-3}}{2}=\frac{ 4 - (-3)}{4} = \]

Answer 6

which gives an answer of
\[\frac{7}{4}\]

Answer 7

7/4 is the answer to question 2

Answer 8

thank you @campbell_st

Answer 9

\[\sqrt{12}\over \sqrt{-6}\]\[2\sqrt{3}\over \sqrt{3}\sqrt{-2}\]\[2\over \sqrt{-2}\]\[2\sqrt{-2}\over-2\]\[-\sqrt{2}\sqrt{-1}=-i \sqrt{2}\]