Question

If Logx (1 / 8) = - 3 / 2, then x is equal to

A. - 4
B. 4
C. 1 / 4
D. 10

Answer 1

\[x^{-\frac{3}{2}}=\frac{1}{8}\]
\[x^{\frac{3}{2}}=8\]
\[x^3=64\]
\[x=\sqrt[3]{64}=4\]

Answer 2

initial step is important one
\[\log_b(x)=y\iff b^y=x\]

Answer 3

thanks!!! that helps a lot!!!!!:D