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Mathematics 10 Online
OpenStudy (anonymous):

Help me simplify? Question: http://www.mathway.com/math_image.aspx?p=SMB02FSMB03SMB02FSMB034SMB10x-3SMB02fSMB03+SMB02FSMB032SMB103SMB02fSMB03SMB10SMB02FSMB035SMB10x-3SMB02fSMB03SMB02fSMB03?p=57?p=82 It was too complicated to write so I had to put it through mathway. :(

OpenStudy (anonymous):

you have a choice. multiply top and bottom by \(3(x-3)\) to clear the fractions or actually add in the numerator and then invert and multiply which would you like to do?

OpenStudy (anonymous):

Multiply top and bottom, seems more straight forward.

OpenStudy (anonymous):

ok we can write it out \[\frac{\frac{4}{x+3}+\frac{2}{3}}{\frac{5}{x+3}}\] \[\frac{\frac{4}{x+3}+\frac{2}{3}}{\frac{5}{x+3}}=\times \frac{3(x+3)}{3(x+3)}\] \[=\frac{4\times3+2(x+3)}{5\times 3}\] then some algebra

OpenStudy (alexwee123):

i fail its a plus not minus sign :/

OpenStudy (anonymous):

K, I see the set up now, thanks for the help. I can take it from here. :)

OpenStudy (anonymous):

@alexwee123 It's ok.

OpenStudy (anonymous):

\[\frac{\frac{4}{x+3}+\frac{2}{3}}{\frac{5}{x+3}}\times \frac{3(x+3)}{3(x+3)}\] \[=\frac{4\times3+2(x+3)}{5\times 3}\] \[=\frac{12+2x+6}{15}=\frac{18+2x}{15}\]

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