Help me simplify? Question: http://www.mathway.com/math_image.aspx?p=SMB02FSMB03SMB02FSMB034SMB10x-3SMB02fSMB03+SMB02FSMB032SMB103SMB02fSMB03SMB10SMB02FSMB035SMB10x-3SMB02fSMB03SMB02fSMB03?p=57?p=82 It was too complicated to write so I had to put it through mathway. :(
you have a choice. multiply top and bottom by \(3(x-3)\) to clear the fractions or actually add in the numerator and then invert and multiply which would you like to do?
Multiply top and bottom, seems more straight forward.
ok we can write it out \[\frac{\frac{4}{x+3}+\frac{2}{3}}{\frac{5}{x+3}}\] \[\frac{\frac{4}{x+3}+\frac{2}{3}}{\frac{5}{x+3}}=\times \frac{3(x+3)}{3(x+3)}\] \[=\frac{4\times3+2(x+3)}{5\times 3}\] then some algebra
i fail its a plus not minus sign :/
K, I see the set up now, thanks for the help. I can take it from here. :)
@alexwee123 It's ok.
\[\frac{\frac{4}{x+3}+\frac{2}{3}}{\frac{5}{x+3}}\times \frac{3(x+3)}{3(x+3)}\] \[=\frac{4\times3+2(x+3)}{5\times 3}\] \[=\frac{12+2x+6}{15}=\frac{18+2x}{15}\]
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