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Mathematics 15 Online
OpenStudy (konradzuse):

find the area of the region

OpenStudy (konradzuse):

\[\int\limits_{0}^{7} 8x * \sqrt[3]{x +1} dx\]

OpenStudy (konradzuse):

OpenStudy (anonymous):

Let \(u=x+1\) might work.

OpenStudy (anonymous):

try \(u=x+1\)

OpenStudy (konradzuse):

do I just integrate like normal? These questions always konfuse me :P

OpenStudy (anonymous):

then \(x=u-1\) so you get \[8\int (u-1)\sqrt{u}du\]

OpenStudy (anonymous):

to the power of 3.

OpenStudy (anonymous):

actually it would be \[8\int(u-1)\sqrt[3]{u}du\]

OpenStudy (anonymous):

Then expand and integrate normally.

OpenStudy (anonymous):

when i try to solve, someone has done! -.-

OpenStudy (anonymous):

\[8\left(\int u^{\frac{4}{3}}-\int u^{\frac{1}{3}}du\right)\]etc

OpenStudy (konradzuse):

\[\int\limits \frac{3u^{7/3}}{7} -\int\limits \frac{3u^{4/3}}{4} \] ???

OpenStudy (konradzuse):

err * 8 :P so 24

OpenStudy (konradzuse):

+c of course :)

OpenStudy (anonymous):

When you integrate the integral is not there; you can't just leave the integral like that.

OpenStudy (konradzuse):

yeah sorry I messed up lol :P Is the rest of it correct? :)

OpenStudy (konradzuse):

and change u into x+1... SO that's the area of the region?

OpenStudy (anonymous):

I dont think so its suppose to be\[\frac{24u^{\frac{7}{3}}}{7} -6u^{\frac{4}{3}} +C\]

OpenStudy (konradzuse):

yup that's what I got if i multiplied by 8 which I forgo to :P. So that's the area?

OpenStudy (anonymous):

Remmember to sub in the \(x+1\) and don't forget the limits.

OpenStudy (konradzuse):

\[\frac{24(x+1)^{7/3}}{7} - 6(x-1)^{4/3} 0-7\]

OpenStudy (anonymous):

Hm, why did you add the \(0\) out of no where?

OpenStudy (konradzuse):

Thos ewere my limits sorry.

OpenStudy (konradzuse):

\[\frac{24(7+1)^{7/3}}{7} - 6(7-1)^{4/3}\] =\[\frac{24(8)^{7/3}}{7} - 6(6)^{4/3}\] = \[\frac{3072}{7} - 6(6)^{4/3}\] which I'm not sure what the fractin is of that...

OpenStudy (konradzuse):

6^(4/3) is 10.90272355699284

OpenStudy (anonymous):

It looks as though you subbed in the limits right. The other part is just simple. :)

OpenStudy (konradzuse):

Yeah I'm konfused :(

OpenStudy (anonymous):

Why so?

OpenStudy (konradzuse):

I'm stuck at how to figure out the 6(6)^(3/4) Idk how to get it as a fraction, or what do i do?

OpenStudy (anonymous):

You can leave it as fractions. It depends on the question. But I don't really like decimals. :)

OpenStudy (konradzuse):

but what is the fractin of it?

OpenStudy (konradzuse):

I cannot get a fraction out of 65.4123128

OpenStudy (konradzuse):

so it's 3072/7 - ???? :(

OpenStudy (konradzuse):

6^(4/3) = 10.90272355699284 * 6 = 65.41634134195704

OpenStudy (konradzuse):

Apparently 373.441 should be the decimal answer?

OpenStudy (anonymous):

Sorry, I dont have a calculator with me.

OpenStudy (konradzuse):

http://web2.0calc.com/

OpenStudy (konradzuse):

oh woops it's 6(x+1) huh...

OpenStudy (konradzuse):

so 96 is the other answer...

OpenStudy (anonymous):

However; http://www.wolframalpha.com/input/?i=integrate+8x%28x%2B1%29%5E%281%2F3%29+from+7+to+0 iif you want verify your answer. (:

OpenStudy (konradzuse):

Yeah thanks, I really messed up lol :(. Did 6(x-1) instead of x+1 I was wondering aobut that lol.. 96 * 7 / 7 3072/7 - that :)

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