Question

find the slope-intercept equation of the line that has the given characteristics
slope 0 and y intercept (0,3)

Answer 1

Slope Intercept form of a line
\[y=mx+c\]
m= slope of the line
c= y intercept
Just plugin the numbers and you'll get the line's equation

Answer 2

so the equation should read y=0x+(0,3)

Answer 3

nope, just y part of the intercept
\[(0, 3)=> 3\]
\[y=0\times x +3\]

Answer 4

so equation should read y=0x+3

Answer 5

yeah, do you understand?

Answer 6

yea now i do

Answer 7

thanks

Answer 8

:D

Answer 9

so an equation for m=3/4,(3,-2)
is y=3/4x+-2

Answer 10

nope, if x=0 then only it's a y-intercept, to find y intercept or c
\[y=mx+c\]
We have m with us
\[y=\frac 34 x+c\]
to find c, put the given point
(3, -2)
\[-2=\frac 34 \times 3+c\]
Now find c and then write the equation!!

Answer 11

the ? reads find an equation of the line having the given slope and containing the given point m=3/4,(3,-2)

Answer 12

and the answer starts out with y=

Answer 13

find c and then plugin the numbers in
\[y=mx+c\]

Answer 14

i dont understand what you mean

Answer 15

cause so far all i have is y=3/4x+b

Answer 16

The equation is give as
\[y=mx+c\]
We have m given as 3/4 and we need to find c
\[y=\frac 3 4x+c...................eq(1)\]
for that use the point (3, -2)
Since the line passes through (3, -2). This point will satisfy the line's equation
put x=3 and y=-2 in eq (1) and find c

Answer 17

so next step is -2=2.25+c

Answer 18

and then -2.25-2=-2.25+2.25+c

Answer 19

then answer should 4.25=c