The base of a triangle measures 10 in. If the area of the triangle is less than 27 in2, what are the possible measures of the height? h=height
well the area of the triangle would be \[1/2 bh\] so \[1/2 \times 10 h < 27\] Now solve the inequality for h
i dont know how to do that
\[5h<27\] Can you do it now?
5.4 ? @beeqay
\[h<5.4\] So your h could be any value less than 5.4in
But then remember, area of a triangle cannot be negative or zero. So h could never be negative or zero.
is the answer h >5.4 ?
No, \[h<5.4\] still holds, we do not need to flip the inequality. We just need to restrict it such that h can never be zero or less than zero. So you will need to introduce something to h<5.4 Any ideas?
i didnt mean to flip it, im just tired
Ok so h should be greater than zero but less than 5.4. Now do you know what the answer is?
no clue
\[0<h<5.4\] This is the expression of my previous statement and your answer.
thanks
No problem.
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