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Consider the vector v=(-6, 13).... Please help if u are good with vectors...? Consider the vector v=(-6, 13). Part 1: Use the dot product to find the angle (in degrees) between v=(-6, 13) and the vector (1,0). i think the answer is -6 Part 2: Write v in the form (absolutevalueof v costheta, absolutevalueof v sintheta) Express the angle theta in degrees. Part 3: Use the dot product of the vectors v=(-6,13) and w=(-42,-34) to determine if they are orthogonal.
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-6 + 0 = -6 angle = cos^-1 (sqroot(6^2) / ( (sqroot(6^2 + 13^2) x sqroot(1^2) )
thats just part 1
ok so part 1 is -6 @javawarrior
are you saying the angle is -6 degrees?
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