A baseball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 10. (h = height, t = time in seconds)
Find the maximum height of the ball.
a) 2.3 feet
b) 23 feet
c) 10 feet
d) 26 feet

Question

A baseball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 10. (h = height, t = time in seconds)
Find the maximum height of the ball. 
 a) 2.3 feet 
 b) 23 feet 
 c) 10 feet 
 d) 26 feet

anonymous · Answer

You can differentiate it to find the maximum.
$h'(t)=( -16*2)t+32$

anonymous · Answer

after differentiaton.....
place the obtained t value in h(t).....
u get the maximum  height!!!

anonymous · Answer

$$v(t)=h ^\prime(t)=0$$
$$-32t+32=0$$
$$t=1$$
after 1 second  the ball is at its maximum
$$h(1)=-16(1)^{2}+32(1)+10=26$$

anonymous · Answer

at the maximum velocity is 0

anonymous · Answer

I Got The answer