A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.
a) 13.9 feet
b) 8.3 feet
c) 12.2 feet
d) 7.6 feet

Question

A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.  
 a) 13.9 feet 
 b) 8.3 feet 
 c) 12.2 feet 
 d) 7.6 feet

kropot72 · Answer

First step is to differentiate with respect to t. Then put the result equal to zero and solve to find the value of t that gives a maximum.
Can you differentiate the equation?

anonymous · Answer

help pls

anonymous · Answer

maximum height occurs at the vertex... t=-b/(2a)=-32/(2*-16)=1
h(1)= -16(1)^2+32(1)+5=21??

kropot72 · Answer

None of the answers given with the question is correct.

anonymous · Answer

agree...^^^