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OpenStudy (aravindg):
1
OpenStudy (aravindg):
sum of coefficennts =0 so 1 is definitely a root
Parth (parthkohli):
Zeros of a function are the values of the variable(s) that bring the function to 0.
\( \color{Black}{\Rightarrow 0 = -x^2 - 2x + 3}\)
Here equate it with zero and then find the values of \(x\).
OpenStudy (cwrw238):
you can write this as
x^2 + 2x - 3 = 0
this can be factored
OpenStudy (cwrw238):
and solved
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OpenStudy (anonymous):
1 and -3 if i am not wrong :)
OpenStudy (aravindg):
yep u r right
OpenStudy (cwrw238):
yep - right
OpenStudy (anonymous):
thank you :)
OpenStudy (cwrw238):
yw
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Parth (parthkohli):
And thus, it's a victory of direct answering
OpenStudy (aravindg):
:(
OpenStudy (anonymous):
u can use a formula here too
x={-b+-(b*b - 4ac)^1/2}/2a if u can relate ;)
OpenStudy (aravindg):
@abhijitjain1995 i dont see any reason y u need to use that
OpenStudy (aravindg):
@ParthKohli i am against that :)
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OpenStudy (cwrw238):
its easier to factor
OpenStudy (aravindg):
yep @cwrw238
Parth (parthkohli):
@AravindG yay!
OpenStudy (anonymous):
i factored it manually . Any quad eqn is of the form -> ax*x + bx +c = 0 . U can have many approaches to a single problem people.
OpenStudy (aravindg):
i should add to it that some approaches gain momentum than others in specific qn and this was a beautiful example :)
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