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Find the area of a circle circumscribed about an equilateral triangle whose side is 18 inches long.
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you'll note that it splits the angles in two. We can solve for the radius using trig. We have a 30-120-30 triangle: sin(30)=r/18 18sin(30)=r=9 We can now solve for the circle are: Area=πr2=π(9)2=81π=
That last part should say = 254.47
you can find the area of each segment using A = 0.5 r^2 A - area of triangle where A = pi/3 radians area of triangle = 0.5*18^2 sin pi/3
thx guys appreciated it :)
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yw
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