Question

If A = {positive integers divisible by 2} and B = {integers}, what is A ∩ B?

{ }

{2, 4, 6, 8 …}

{2, 4, 6, 8, 10}

{1, 2, 3, 4, 5 …}

Answer 1

'Intersection'. Do you remember what the guys told you in the last question?

Answer 2

Anyway, the intersection is just a set of common elements in two given sets.

Answer 3

so since A = {positive integers divisible by 2} and B = {integers}
then A ∩ B={all positive integers that are divisible by two}

which answer is that?

Answer 4

im stuck with C and D

Answer 5

are all the entries in D divisible by 2 ?

Answer 6

so its C

Answer 7

does C contain every possible integer that is divisible by 2 ?

Answer 8

im horrible in math but yeah i think so

Answer 9

I think 12 is not on that list, yet it is divisible by 2
actually no number higher than 12 is on the list, so it is only a subset of \(A\cup B\)
which set has \(all\) integers divisible by 2 ?

hint: the symbol "..." means "the pattern continues indefinitely"

Answer 10

positive integers*

Answer 11

so its B because it continues

Answer 12

yes :)

Answer 13

thank you