Question

Find the coefficient of x^6 in (1-3x)^2(x+2)^8 (using binomial theorem)

Answer 1

The expanded form from wolfram showed me that the coefficient is 7504...

Answer 2

What is your original function?
I was guessing what it is?

Answer 3

sorry, i made a mistake on my question (1-3x)^2(x+2)^8

Answer 4

In this case, it is 7504

Answer 5

yes, how did you get that?

Answer 6

\[
(1-3 x)^2=9 x^2-6 x+1
\]
That is easy.
How do you get now x^6

Answer 7

i multiply in the (x+2)^8

Answer 8

you get it from the terms x^6, x^5 and x^4 multiplying the terms 1, -6 x, 9 x^2

Answer 9

What are they?