Question

Limit Evaluation:

Answer 1

\[\Huge \lim_{x \rightarrow 0} \frac{(2+h)^3 -8}{h} \]

Answer 2

it's a function of h and x->0

Answer 3

if it's h->0, expand that cube ... cancel out 8, then cancel out h on top and bottom ad get your answer

Answer 4

How do I do that?

Answer 5

(2+h)^3 = 8 + h^3+3*2*h(h+2)

Answer 6

http://www.wolframalpha.com/input/?i=%282%2Bh%29^3-8

Answer 7

or use L' hospital's rule..ans=4

Answer 8

my bad
(2+h)^3 = 8 + h^3+3*h(h+2)

Answer 9

must be 6

Answer 10

but by differenting numerator becomes 3*(h+2)^2 = 12

Answer 11

Oh ...
so .. (2+h)^3 = 8 + h^3+3*2*h(h+2) was right ... lol