where does the graph of y=2x2-x-3 cross as the x-axis?
Hi ivogel3 :) How are you dear ? :D
good
So we have to find the point on x-axis, known as x-intercept also. Right?
yes i need to answers
Well we know at x-axis the coordinate of y is 0 And at y-axis the coordinate of x is 0. OK dear.
ok
So in order to find x-intercept we have to put y=0
if the equation is already equal to zero then what
Your equation becomes. \[\large x^2-x-3=0\] Now solve it.
Then just solve it simply.
(x )(x ) but is other number that goes into the parenthasses
I know you can solve it now. You must get 2 answers.
what about the 2
Do you know how to use the quadratic formula?
\(\huge x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) Where \(a=2;~~b=-1;~~c=-3\)
\(\huge x= \frac{-(-1) \pm \sqrt{(-1)^2-4(2)(-3)}}{2(2)}\)
\(\huge x= \frac{1 \pm \sqrt{1+24}}{4}=\frac{1\pm\sqrt{25}}{4}=\frac{1\pm5}{4}\)
X= -1 and x = 1.5
@dq101, please read the Code of Conduct; http://openstudy.com/code-of-conduct Don't give out straight answers :)
@zepp, my bad! :$ I'm still new here!
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