Question

find the coefficient of x^3 in the expansion of (3x+2)^8

Answer 1

\[\dbinom{8}{3}(3x)^32^5\] is the term you are looking for

Answer 2

\[\dbinom{8}{3}=\frac{8\times 7\times 6}{3\times 2}=8\times 7=56\]
\[3^3=27\]
\[2^5=32\] multiply those numbers together to get your coefficient

Answer 3

how do you find the first part ?

Answer 4

Since the power 8, and the third element is the one you pick on!

Answer 5

i don't know what "the first part" is

Answer 6

if you mean \(\binom{8}{3}\) that is because you want \(x\) to the power of 3, and you are raising this binomial to the power of 8