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Mathematics 11 Online
OpenStudy (anonymous):

When an object is removed from a furnace and placed in an environment with a constant temperature of 80F, its core temperature is 1500F. One hour after it is removed, the core temperature is 1120F. Find the course temperature 5 hours after the object is removed from the furnace. (Hint: This is Newton's Law of Cooling problem). Please help me!

OpenStudy (anonymous):

first off work with the differences in the temperatures, not the temperatures themselves

OpenStudy (anonymous):

\(1500-80=1420\) and \(1120-80=1040\) so it is like saying it cooled from 1420 to 1040 in one hour

OpenStudy (anonymous):

since the rate of change is proportional to the current amount (exponential decay) you can model this as \[A=\left(\frac{1040}{1420}\right)^t\] or \[A=\left(\frac{52}{71}\right)^t\] where A represents the difference in the heated temp and the ambient temp (just add 80 at the end)

OpenStudy (anonymous):

to get your answer replace \(t\) by 5, and then don't forget to add the 80 degrees

OpenStudy (anonymous):

Okay, got it. Thanks again, you're a life saver!

OpenStudy (anonymous):

yw btw you can do this a different way using \(A_0e^{kt}\)but it requires more work and is less accurate not sure what you teacher wants

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