Question

Matt bought an outdoor wall light fixture. The fixture has semicircular ends at the top and bottom as shown. The side of the fixture that faces the wall is open.

A light fixture shaped as a half cylinder with a diameter of 8 inches and height of 14 inches.

What is the exterior surface area of the light fixture?

44π in2

56 in2

72π in2

105π in2

Answer 1

surface area of the semi-circles: A = π r^2 (r=4)
surface area of the curved side: A=(π)(r)(h) (r=4, h=14)

then add it all together.

Answer 2

=224pi

Answer 3

im confused!

Answer 4

A = π r^2

A = π 4^2

A = 16π

So the area of the semi circle top and bottom combine is 16π sq inches

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A = π*r*h

A = π*4*14

A = 56π

and the area of the curved (lateral) surface is 56π

Answer 5

Now add the two areas: 16π + 56π = 72π

Answer 6

So the answer is 72π

Answer 7

thanks @anuragtripathi and @jim_thompson5910<3

Answer 8

you're welcome

Answer 9

welcome