what is the derivative of Absolute x / x by definition?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[{|x| \over x}\] is not continuous
OpenStudy (freckles):
for x>0 |x|=x
for x<0 |x|=-x
correct?
OpenStudy (freckles):
So for your function the right derivative and the left derivative of 0 will be different so the derivative at x=0 will not exist
OpenStudy (anonymous):
can you show me the steps?
OpenStudy (freckles):
Can I show you the steps for for
x>0 |x|=x
x<0 |x|=-x
?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (freckles):
This is by definition.
OpenStudy (freckles):
|x|=x whenever x>0
|x|=-x whenever x<0
|x|=0 whenever x=0
|x|/x=x/x when x>0
|x|/x=-x/x when x<0
The derivative doesn't exist at x=0 because the function didn't exist at x=0
OpenStudy (freckles):
Now I haven't differentiated our piecewise function yet
OpenStudy (freckles):
I'm sure you can do (x/x)' for x>0
and (-x/x)' for x<0
since both of these functions are constants
OpenStudy (anonymous):
if by using the differentiation principle?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Find the absolute maximum and minimum of function x-2sinx over a interval [-pi,pi]