Question

Someone want to explain Kirshoff's

Answer 1

There are two laws:
1. Kirchoff's Current Law (KCL): At any wire junction, the signed sum of the associated currents add up to zero. (The amount of current going into a junction is the amount of current exiting the junction).
2. Kirchoff's Voltage Law (KVL): The integral \(\oint \vec E \cdot d\vec \ell\) about any closed wire loop is equal to zero. Some teachers like to phrase this as all the voltage drops about a closed loop add up to zero (or cancel out). (NOTE: this law only holds when there isn't a changing magnetic field...we must otherwise use Faraday's law.)

Does that make sense?

Answer 2

Kirchhoff's Second Law states that in any mesh of a network the algebraic sum of the voltages is equal to the algebraic sum of the products of the resistances and the respective currents of the separate parts.
For any mesh or closed part of the circuit\[\sum_{}^{}E=\sum_{}^{}(IR)\]
In effect this second law is a particular application of Ohm's law to a portion of the circuit

Answer 3

@kropot72 - It's not only for resistors. Kirchoff's Second Law is more general, applying to components such as capacitors and batteries as well, which, can ideally have no resistance.