y / y^2-y-20 - 2 / y+4 HELP APPRECIATED
factor the first denominator (y^2 - y - 20) into (y-5)(y+4) now, do you see what you need to do to get a common denominator?
how do you get rid of the y^2
PLease use brackets. @j-free
is this your expression? \[\huge \frac{y}{y^2-y-20}-\frac{2}{y+4} \]
that's HUGE.
(y/y^2-y-20) - (2/y+4)
yes... it is... among other things... :)
@dpaInc YES YES
Indeed. ;D
@j-free , started you off with factorizing the denominator of that first rational expression. can you get that second fraction to have the common denominator?
i meant @BTaylor ... ^^^
2(y+2)
not quite. you need to multiply the entire second term by (y-5)/(y-5)
y+4/y-5
y+20/y+25
\[\frac{y}{(y+4)(y-5)}-\frac{2(y-5)}{(y+4)(y-5)}\] now combine the numerators...
y-5 right?
no, you get as your numerator y-2y+10 --> 10-y I believe that is as simple as you can make it.
dont the denominators just cancel out now?
no, the final answer is \[\frac{10-y}{(y+4)(y-5)}\] I just didn't include the denominator in my last response.
10-y / y^2-20
no, 10-y / y^2-y-20
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