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Mathematics 16 Online
OpenStudy (anonymous):

divide: (8x^3+12x^+14x-10) / (2x) a. 4x^2+6x+7-5/x b. 4x^2+6x+7-5 c. 6x^2+10x+12-5/2x d. 4x^2+12x+7-5/x

jimthompson5910 (jim_thompson5910):

what is the GCF of the terms in the numerator?

OpenStudy (anonymous):

what numerator?

jimthompson5910 (jim_thompson5910):

the terms 8x^3+12x^2+14x-10 are all in the numerator

OpenStudy (anonymous):

but the equation isnt written as a fraction its the division symbol so would i still make that the numerator?

jimthompson5910 (jim_thompson5910):

a fraction symbol is a division symbol, they're both the same.

jimthompson5910 (jim_thompson5910):

1/2 = one half = 0.5

OpenStudy (anonymous):

ohh okay.. i dont know how to get the GCF for the numerator

jimthompson5910 (jim_thompson5910):

what is the GCF of 8, 12, 14, and 10?

OpenStudy (anonymous):

2 or 4?

jimthompson5910 (jim_thompson5910):

it's 2

jimthompson5910 (jim_thompson5910):

so you can factor out this GCF from the numerator to go from 8x^3+12x^2+14x-10 to 2(4x^3+6x^2+7x-5)

OpenStudy (anonymous):

so do i divide 2 from the parenthesis's?

jimthompson5910 (jim_thompson5910):

yes the two's will cancel out

OpenStudy (anonymous):

4x^2+6+7-x^5 or 4x^2+6+7-x^5/x i think its the second one?

jimthompson5910 (jim_thompson5910):

oh i see what they did, very strange move, but I guess it works

jimthompson5910 (jim_thompson5910):

they factored a 2x from the first three terms to get 2x(4x^2+6x+7) Then they canceled the 2x terms This means (8x^3+12x^2+14x-10)/(2x) becomes 4x^2+6x+7 - 10/(2x) Then they reduced -10/2x to get -5/x so the final answer is 4x^2+6x+7 - 5/x, which is choice A

OpenStudy (anonymous):

okay thanks alot

jimthompson5910 (jim_thompson5910):

yw

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