Question

57. What is the percentage of water in the hydrate CoCl2 • 6H2O? Show your work. (3 points)

Answer 1

find the molecular weights of \(\large CoCl_2\) & \(\large H_2O\)

Answer 2

Percentage mass,

Answer 3

\[{6(H_2O) \over (CoCl_2)+6(H_2O)} \times 100\%\]

Answer 4

in rough figures im getting a bit under 50%

Answer 5

\[(\% w_{H_2O}/w_{{CoCl}_2\cdot 6H_2O})=\frac{M_{6H_2O}}{M_{{{CoCl}_2\cdot 6H_2O}}}\]\[={6M_{H_2O} \over M_{CoCl_2}+6M_{H_2O}}\]\[=\frac{6\times(2\times M_H+M_O)}{M_{Co}+2\times M_{Cl}+6\times(2\times M_H+M_O)}\]
\[M_H=1.01\text u\]\[M_O=16.00 \text u\]\[M_{Co}=58.93 \text u\]\[M_{Cl}=35.45\text u\]